Answer:
The maximum error in the calculated value of α is 0.00876712328767 radians.
Step-by-step explanation:
Let us suppose the legs of the right triangle are x and y.
So, we have
x = 40 cm, y = 80 cm, dx = 0.5, dy = 0.8
We have to find maximum error in α for
[tex]\alpha=\frac{y}{x}[/tex]
Now, find the differentials with respect to x and y
Partial differential of α with respect to x
[tex]\frac{\partial \alpha}{\partial x}=\frac{\partial }{\partial x}(arctan\:\left(\frac{y}{x}\right))\\\\\frac{\partial \alpha}{\partial y}=\-\frac{y}{y^2+x^2}}[/tex]
Similarly, partial differential of α with respect to y
[tex]\frac{\partial \alpha}{\partial y}=\frac{\partial }{\partial y}(arctan\:\left(\frac{y}{x}\right))\\\\\frac{\partial \alpha}{\partial y}=\frac{x}{y^2+x^2}[/tex]
The maximum error in calculated value of α is given by
[tex]d\alpha=\left | \frac{\partial \alpha}{\partial x}\cdot dx \right |+\left | \frac{\partial \alpha}{\partial y}\cdot dy \right |[/tex]
Substituting the known values, we get
[tex]d\alpha=\left | -\frac{80}{80^2+30^2}\cdot 0.5 \right |+\left | \frac{30}{80^2+30^2}\cdot 0.8 \right |[/tex]
Simplifying, we get
[tex]d\alpha=\left | -0.00547945205479 \right |+\left |0.00328767123288 \right |\\\\d\alpha=0.00547945205479+0.00328767123288\\\\d\alpha=0.00876712328767\text{ radians}[/tex]
Therefore, the maximum error in the calculated value of α is 0.00876712328767 radians.