Explanation:
Refer the given figure showing the arrangement.
For having stability we have torque at A and B are zero.
Sum of Torques at A = 0
700 x 1 + 200 x 1.5 - Q x 3 = 0
3Q = 1000
Q = 333.33 N
Sum of Torques at B = 0
200 x 1.5 + 700 x 2 - P x 3 = 0
3P = 1700
P = 566.67 N
Tension in ropes are 333.33 N and 566.67 N.
Tension in each rope, which supports the scaffold on which window washer is standing, are 333.33 N and 566.67 N.
Tension is the pulling force carried by the flexible mediums like ropes, cables, and string. Tension in a body due to the weight of the hanging body is the net force acting on the body.
Let the force acting on the point B is O. The summation of the torque at the point A for the attached figure,
[tex]\sum \tau_A=0\\700\times1+200\times1.5-O\times3=0\\O=333.33\rm N[/tex]
Let the force acting on the point A is N. Now, the summation of the torque at the point for the attached figure,
[tex]\sum \tau_B=0\\700\times2+200\times1.5-N\times3=0\\N=566.67\rm N[/tex]
Hence, the tension in each rope, which supports the scaffold on which the window washer is standing, are 333.33 N and 566.67 N.
Learn more about the tension in the string here;
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