Respuesta :
Answer:
Total work done is W = 0 j
work done by gravity ,W = - 30000 J ON THE BASIS OF TOP SPEED
Explanation:
given data:
mass of roller coaster is 200 kg
max height is 30 m
top speed is 30 m/s
height of section from starting point is 5 m
from work energy theorem
Work done [tex]= \Delta U_{G} + \Delta U_{E} + \Delta KE[/tex]
as there is no elastic force so we have
work done is [tex]\Delta U_{G} + \Delta KE[/tex]
total work done is [tex]W = 0 + \Delta KE[/tex]
[tex]W = \frac{1}{2} mv^2 + \frac{1}{2} mv^2[/tex]
W = 0 j
work done by gravitational force is W = mgh
[tex]W = 200 \times 30 \times 5 = 30000 J[/tex]
W = - 30000 J ON THE BASIS OF TOP SPEED
here -ve sign indicate that body moves in opposite direction of gravity force
Answe
given,
mass of roller coaster = 200 Kg
maximum height reached = 30 m/s
top speed = 30 m/s
time = 40 s
no elastic spring force is acting so, the total energy is conserved in the system.
The potential and kinetic energy of the roller coaster is conserved in this system.
We know that work done by the conservative force is equal to here and in this case there is no non conservative force like frictional force or spring force acting on it.
Hence work done by the roller coaster will be zero.
a) Work done
[tex]W = KE_2 - KE_1[/tex]
[tex]W =\dfrac{1}{2}mv^2 - \dfrac{1}{2}mv^2 [/tex]
[tex]W =0\ J[/tex]
b) Work done by gravity
W = m g h
W = 200 x (-9.8 ) x 5
negative sign represent work done by the gravitational force is in negative direction.
W = -9800 N
