contestada

27. A 0.150 kg baseball is thrown upward with an initial
speed of 20.0 m/s.
a. What is the force on the ball when it reaches
half of its maximum height? (Disregard air
resistance.)
b. What is the force on the ball when it reaches
its peak?

Respuesta :

Answer:

a. [tex]1.47N[/tex]

b. [tex]1.47N[/tex]

Explanation:

Given:

Mass of the baseball = [tex]0.150kg[/tex]

The initial velocity of the baseball = 20m/s

The force acting on the baseball is only due to gravity and the air resistance is negligible. The baseball acceleration is constant due to gravity.

According to Newton's second law:

[tex]F_{w} =mg[/tex]----------(1)

where mass of the baseball [tex]m = 0.150kg

And acceleration due to gravity [tex]g = 9.8m/s^{2}[/tex]

Put all the value in equation 1.

[tex]F_{w} =0.150\times -9.8[/tex]

[tex]F_{w} =-1.47N[/tex]

Therefore, the force on the ball when it reaches half of its maximum height is [tex]1.47N[/tex].

Similarly, the force acting on the ball when its peak [tex]1.47N[/tex].