There is a typo error in the last part of the question. The corrected part is-
"If the probability that she orders just a grilled cheese sandwich is .76, what is the probability that she will order a grilled cheese or fries?"
Answer:
The probability that she will order a grilled cheese sandwich or fries is 0.43.
Step-by-step explanation:
Given:
Probability of ordering fries is, [tex]P(F)=0.32[/tex]
Probability of ordering cheese sandwich is, [tex]P(S)=0.76[/tex]
Probability of ordering both sandwich and fries is, [tex]P(F\cap S)=0.65[/tex]
Probability of ordering cheese sandwich or fries is given by the union of both the events 'F' and 'S' given as [tex]P(F\cup S)[/tex].
Now, using addition theorem of probability, we get:
[tex]P(F\cup S)=P(F)+P(S)-P(F\cap S)\\P(F\cup S)=0.32+0.76-0.65\\P(F\cup S)=0.43[/tex]
Therefore, probability of ordering cheese sandwich or fries is 0.43.
