Determine the gravitational force of attraction between two 3.5 kg bowling balls whose
centers are exactly 2.0 meters from each other.
F 3.06 N
G 7.00 N
H 4.09 x 10-10 N
J 2.04 x10-10 N

Respuesta :

Answer:

[tex]F_G=2.04\ .\ 10^{-10}\ Nw[/tex]

Option J

Step-by-step explanation:

Newton's Universal Law Of Gravitation

Newton discovered that all objects attract each other with a force of gravitational attraction which is proportional to their masses and inversely proportional to the square of the distance between them.

[tex]\displaystyle F_G=G\frac{m_1m_2}{d^2}\ ,\ G=6.673\ .\ 10^{-11} N m^2/kg^2[/tex]

Where [tex]m_1, m_2[/tex] are the masses in kg and d is the distance between them in meters.

In the problem, we have

[tex]m_1=m_2=3.5\ kg[/tex]

[tex]d=2\ meters[/tex]

[tex]\displaystyle F_G=6.673\ .\ 10^{-11} N m^2/kg^2\frac{(3.5kg)(3.5kg)}{(2m)^2}[/tex]

[tex]\boxed{F_G=2.04\ .\ 10^{-10}\ Nw}[/tex]