Answer:
maximum revenue is 114005
Step-by-step explanation:
for the function R(p) to attain its maximum value R'(p) must be 0.
that is the slope of R(p) must be 0.
R(p) = [tex]-5p^{2} + 1510p[/tex]
R'(p) = [tex]-10p + 1510[/tex]
therefore [tex]-10p + 1510 = 0[/tex]
therefore R(p) is maximum when p = 151
therefore R(151) = [tex]-5(151^{2} )+1510(151)[/tex]
= 114005
