contestada

You throw a 0.150-kg baseball straight up in the air, giving it an initial upward velocity of magnitude 20.0 m/s. How high does the ball rise? (Ignore the effect of air resistance.)

3.00 m

133 m

14.7 m

20.4 m

Respuesta :

opudodennis

Answer:

Option D

20.4 m

Explanation:

Applying the law of conservation of energy

initial kinetic energy = final potential energy

[tex]0.5mv^{2}=mgh[/tex] where m is the mass, v is the velocity, g is acceleration due to gravity and h is the height.

Making height the subject then

[tex]h=\frac {v^{2}}{2g}[/tex]

Substituting the given value of v as 20 m/s and using acceleration of 9.81 then

[tex]h=\frac {20^{2}}{2\times 9.81}=20.38735984\approx 20.4 m[/tex]

Otras preguntas