Answer:
Acceleration, [tex]a=-18.62\ m/s^2[/tex]
Explanation:
Given that,
Mass of Suzie, m = 76 kg
Initial speed of Suzie, u = 50 mph = 22.35 m/s
Finally, it stops, v = 0
Time, t = 1.2 s
Let a is the Suzie’s average acceleration. It is equal to the rate of change of velocity. Its formula is given by :
[tex]a=\dfrac{v-u}{t}[/tex]
[tex]a=\dfrac{0-22.35}{1.2}[/tex]
[tex]a=-18.62\ m/s^2[/tex]
So, the average acceleration of Suzie’s is [tex]18.62\ m/s^2[/tex] and she is decelerating. Hence, this is the required solution.