The function below takes one parameter: a string (date_string) containing a date in the mm/dd/year format. Complete the function to return a list containing integers for each of the date components in month, day, year order. For example, if given the string '06/11/1930', your code should return the list [6, 11, 1930].

Next, use the Python string split() method to split the date string into a list of date components (month, day & year) and assign it to variable date_list. (Line 3) In this case, we use "/" as the separator.

However, all the separated date components in the date_list are still a string. We can use for-loop to traverse through each of the element within the list and convert each of them to integer using Python int() function. (Line 5 - 6)

At last return the final date_list as the output (Line 8)

We can test our function as in Line 11. We shall see the output is as follow:

[6, 11, 1930]

vintechnology vintechnology · Answer 2 · 2022-03-31T15:56:49+02:00

The function that takes one parameter: a string (date_string) containing a date in the mm/dd/year format and return a list containing integers for each of the date components in month, day, year order is as follows:

def convert_date(date_string):

list1 = []

splits = date_string.split("/")

for i in splits:

list1.append(int(i))

return list1

print(convert_date('06/11/1930'))

Code explanation:

The code is written in python.

We declared a function named "convert_date" and it has a parameter named "date_string".
An empty list is declared.
We used the split() function to remove "/".
We used for loop to loop the variable "splits" and append the integer value of each value in the splits to the list1.
We returned list1.
Finally, we call the function with the required parameter.

learn more on function here: https://brainly.com/question/26104476