Respuesta :
Answer:
answer is 0.1428
Explanation:
Data:- vf=5.0 , vi=0.0 , t=35 , a=? so appling first eq of motion vf=vi+at we have to find a=vf-vi/t , a=5.0-0.0/35 , a=5/35 ,a=0.1428m/sec²
Answer:
[tex]0.14m/s/s[/tex] or [tex]0.14m/s^2[/tex]
Explanation:
Acceleration is the rate at which the velocity of a body increases per unit time. Its S.I unit is meters per second per second. Mathematically it is given as follows;
[tex]a=\frac{v_1-v_o}{t}............(1)[/tex]
where [tex]v_1[/tex] is the velocity, [tex]v_o[/tex] the initial velocity and t is the time taken.
Given;
[tex]v_o=0.0m/s\\v_1=5.0m/s\\t=35s\\a=?[/tex]
We substitute all into equation (1) to calculate a as follows;
[tex]a=\frac{5.0-0.0}{35}\\a=\frac{5}{35}\\a=\frac{1}{7}\\a=0.14m/s/s[/tex]
