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Many species cool themselves by sweating, because as the sweat evaporates, heat is transferred to the surroundings. A human exercising strenuously has an evaporative heat loss rate of about 657 W. If a person exercises strenuously for 28.6 min, how much water must he drink to replenish his fluid loss? The heat of vaporization of water is 2430 J/g at normal skin temperature.

Respuesta :

Answer:

The water lost is 463.95 g.

Explanation:

Given that,

Heat lost rate = 657 W

Time = 28.6 min

Heat vaporization = 2430 J/g

We need to calculate the heat lost

Using formula of heat loss

[tex]heat\ lost =657\times28.6\times60[/tex]

[tex]heat\ lost=1127412\ J[/tex]

We need to calculate the water lost

Using formula of water lost

[tex]water\ lost=\dfrac{heat\ lost}{heat\ vaporization}[/tex]

Put the value into the formula

[tex]water\ lost=\dfrac{1127412}{2430}[/tex]

[tex]water\ lost=463.95\ g[/tex]

Hence, The water lost is 463.95 g.

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