Answer:
a) Q = 8.31 10⁵ J b) M = 0.39 lb
Explanation:
there is a change in temperature and the other where there are changes in state.
Q = m [tex]c_{e}[/tex] ΔT = m [tex]c_{e}[/tex] ([tex]T_{f}[/tex] –T₀)
Q = m L
a) let's look for the heat to melt the ice
Latent heat of ice melting 3.34 105 J / kg
Q₁ = m L
Q₁ = 1.7 3.34 10⁵
Q₁ = 5.678 10⁵ J
water to 37°C
Q₂ = m [tex]c_{e}[/tex] ([tex]T_{f}[/tex]-T₀)
Q₂ = 1.7 4.186 10³ (37 - 0)
Q₂ = 2,632 10⁵ J
The total heat in the process is
Q = Q₁ + Q₂
Q = (5,678 + 2,632) 10⁵ J
Q = 8.31 10⁵ J
b) say that 1lb of fat produces
3500 kcal (4186 J / 1kcal) = 1,465 10⁷ J
Let's use a rule of proportions, if in one day 8.31 10⁵ J is needed to process the ice how much is needed in 7 days
Qt = 7 8.31 10⁵ J
Qt = 58.17 10⁵ J
Amount of fat
M = 1lb (58.17 10⁵ / 1.465 10⁷)
M = 39.70 10⁻² lb
M = 0.39 lb