After playing two football games, a professional football team's defense had given up an average of 28 points per game. After playing a third football game, the team's defense had given up an average of 22 points per game. How many points did the team's defense give up in the third football game? In the third football game, the team's defense gave up nothing points.

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Dryomys Dryomys · Answer 1 · 2019-12-16T06:47:24+01:00

Answer:

In the third football game, the team's defense give up 10 points.

Explanation:

In two games, team has given up average of 28 points per game.

So, total points given up in two games is:

= (28 × 2)

= 56 points.

In three games, team has given up average of 22 points per game.

So, total points given up in three games is:

= (22 × 3)

= 66 points.

Points given up in third game:

= Total points given up in 3 games - Total points given up in 2 games

= 66 points - 56 points

= 10 points

So,

In the third football game, the team's defense give up 10 points.