contestada

An old building is being demolished by swinging a heavy metal ball from a crane. Suppose that such a 100 kg ball swings from a 20-m-long wire at speed 10m/s as the wire passes the vertical orientation. Assume the ball stops after sinking 1.5 m into the wall. What was the average force that the ball exerted on the wall?

Respuesta :

sebasacevedop

Answer:

[tex]F_b=3333N[/tex]

Explanation:

According to Newton's second law, we know that the average force that the ball exerts on the wall is equal to:

[tex]F_b=m_ba_x[/tex]

Now, wa calculate the ball's acceleration, using the following kinetic equation:

[tex]v_f^2=v_0^2+2a_xx[/tex]

The ball stops after sinking 1.5 m, so [tex]v_f=0[/tex]. Replacing and solving for [tex]a_x[/tex]:

[tex]a_x=\frac{-v_0^2}{2x}\\a_x=\frac{-(10\frac{m}{s})^2}{2(1.5m)}\\a_x=-33.33\frac{m}{s^2}[/tex]

Finally. we calculate the magnitude of the average force:

[tex]F_b=100kg(33.33\frac{m}{s^2})\\F_b=3333N[/tex]

Otras preguntas