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A chemistry student weighs out 0.027 kg of an unknown solid compound X and adds it to 550. mL of distilled water at 30.° C. After 10 minutes of stirring, only some of the X has dissolved. The student drains off the solution, then washes, dries and weighs the X that did not dissolve. It weighs 0.008 kg.

1) Using the information above, can you calculate the solubility of X?
2) If so, calculate it. Remember to use the correct significant digits and units.

Respuesta :

abiolaraymond1995

Answer:

1. Yes

2.The solubility of X is 34.55g/L

Explanation:

Solubility of  solute refers to how readily a solute will dissolve in a solvent at a particular temperature. Its the amount of moles or grams required to saturate 1dm[tex]^{3}[/tex] or 1 Litre of water.

From the problem, when the liquid was drained off and amount of X which didn't dissolve was measured, it weighed 0.008kg, this means out of 0.027kg, 0.027-0.008 actually dissolved

= 0.019kg*1000 = 19g.

if 19g is required to saturate 550mL at 30°C,

then[tex]\frac{19*1000}{550}[/tex] will saturate 1L

= 34.545g  will saturate 1Litre

The solubility thus is 34.55g/L

 

Oseni

The solubility of X in water at 30 °C would be 34.55 g/L

Solubility

The solubility of a substance in a solvent is the amount of that substance that is capable of dissolving in a measured amount of solvent at a given temperature.

In this case, 0.027 kg of X was added to 550 mL of water at 30 degrees Celsius.

Amount of X that dissolved = 0.027 - 0.008 = 0.019 kg

Solubility of X in water at 30 degrees Celsius = 19/0.55

                                               = 34.55 g/L

More on solubility can be found here: https://brainly.com/question/8591226

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