In a race from point X to point Y and back, Jack averages 30 miles per hour to point Y and 10 miles per hour back to point X. Sandy averages 20 miles per hour in both directions. Between Jack and Sandy, who finished first?

Respuesta :

Answer:

Sandy will finish the race first.

Step-by-step explanation:

Let D be the total one sided distance in miles, ( between X and Y ),

We know that,

[tex]Speed =\frac{Distance}{Time}[/tex]

[tex]\implies Time =\frac{Distance}{Speed}[/tex]

Since, from point X to point Y and back, Jack averages 30 miles per hour to point Y and 10 miles per hour back to point X.

So, the total time taken by Jack = [tex]\frac{D}{30}+\frac{D}{10}[/tex]

[tex]=\frac{D+3D}{30}[/tex]

[tex]=\frac{4D}{30}[/tex]

[tex]=0.1333D[/tex]

Also, Sandy averages 20 miles per hour in both directions,

So, the total time taken by Sandy = [tex]\frac{D}{20}+\frac{D}{20}[/tex]

[tex]=\frac{D+D}{20}[/tex]

[tex]=\frac{2D}{20}[/tex]

[tex]=\frac{D}{10}[/tex]

[tex]=0.10D[/tex]

∵ 0.133D > 0.10D

Hence, Sandy will finish the race first.