Answer:
a. [tex]A = C_{0}(1-x)^t\\x: percentage\ of \ caffeine\ metabolized\\[/tex]
b. [tex]\frac{dA}{dt}= -11.25 \frac{mg}{h}[/tex]
Step-by-step explanation:
First, we need tot find a general expression for the amount of caffeine remaining in the body after certain time. As the problem states that every hour x percent of caffeine leaves the body, we must substract that percentage from the initial quantity of caffeine, by each hour passing. That expression would be:
[tex]A= C_{0}(1-x)^t\\t: time \ in \ hours\\x: percentage \ of \ caffeine\ metabolized\\[/tex]
Then, to find the amount of caffeine metabolized per hour, we need to differentiate the previous equation. Following the differentiation rules we get:
[tex]\frac{dA}{dt} =C_{0}(1-x)^t \ln (1-x)\\\frac{dA}{dt} =100*0.88\ln(0.88)\\\frac{dA}{dt} =-11.25 \frac{mg}{h}[/tex]
The rate is negative as it represents the amount of caffeine leaving the body at certain time.