Answer:
1100, 10pi/3,0.3/pi
Step-by-step explanation:
Given that the population sizes of many animal species rise and fall over time. Suppose that the population size of a certain species can be modeled by the following function.
[tex]P(t) = 3700+ 1100 sin 0.6t[/tex]
We know that sin can take values within -1 and +1, hence minimum is
[tex]3700-1100 = 2600[/tex] and maximum is
[tex]3700 +1100 =4800[/tex]
Amplitude p = 1100
Time for one full cycle of p is we have sin repeats its values after 2pi
i.e. the period if starts from 0, ends in [tex]\frac{2\pi}{0.6} =\frac{10\pi}{3}[/tex]
No of cycles p per year= reciprocal of period = [tex]0.3/\pi[/tex]