Answer:
0.005826
Step-by-step explanation:
Given that the annual rainfall (in inches) in a certain region is normally distributed with mean μ = 40 inches and standard deviation σ = 4 inches
We have each year is independent of the other and there are two outcomes
p = Probability for a particular year to have rainfall of over 50 inches
=P(X>50)
= 1-0.9938
=0.0062
P(X<50) = 0.9938
Reqd probability
= P(X<50) for 10 years * P(X>50) on 11th year
=[tex](0.9938)^{10} *0.0062\\=0.005826[/tex]
Assumptions we made:
Each year is independent of the other.
