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An ice puck of mass m revolves on an icy surface in a circle at speed v at the end of a horizontal string of length L. The tension in the string is T. What is the mass of the puck if the length of the string is 2 m, the string tension is 10 N, and the tangential speed of the puck is 2 m/s.

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Answer:

[tex]m=5kg[/tex]

Explanation:

According to the Newton's second law, in this case, the tension is equal to the mass multiplied by the centripetal acceleration, since is a circular motion.

[tex]T=ma_c[/tex]

The centripetal acceleration is given by:

[tex]a_c=\frac{v^2}{r}[/tex]

Here r is the radius of the circular motion, in this case is equal to the length of the string. Replacing and solving for m:

[tex]T=m\frac{v^2}{L}\\m=\frac{TL}{v^2}\\m=\frac{10N(2m)}{(2\frac{m}{s})^2}\\m=5kg[/tex]

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