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Clara created the poster shown below:

A rectangle is shown. The length of the rectangle is labeled as to length equal to 28 cm, and the width is labeled as width equal to 32 cm.

What would be the dimensions of the poster at fraction 1 over 4 times its current size?

Clara created the poster shown below A rectangle is shown The length of the rectangle is labeled as to length equal to 28 cm and the width is labeled as width e class=

Respuesta :

luisejr77

Answer:

[tex]length=4\ cm\\width=6\ cm[/tex]

Step-by-step explanation:

Given the rectangular poster shown in the picture, you know that its dimensions (its width and its lenght) are:

[tex]w_1=24\ cm\\l_1=16\ cm[/tex]

In order to calculate the dimensions of the rectangular  at [tex]\frac{1}{4}[/tex] times its current size, you need to multiply the original lenght by [tex]\frac{1}{4}[/tex] and multiply the original width by [tex]\frac{1}{4}[/tex].

Knowing this, you get:

[tex]w_2=w_1\frac{1}{4}\\\\w_2=(24\ cm)(\frac{1}{4})\\\\w_2=6\ cm\\\\\\l_2=l_1\frac{1}{4}\\\\l_2=(16\ cm)(\frac{1}{4})\\\\l_2=4\ cm[/tex]

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