Respuesta :
Answer:
Useful Work = 899.8 J
Explanation:
Efficiency = [tex]\mathbf{\frac{Useful \ Work}{Total \ Work}\times100}[/tex]
Useful Work = [tex]\mathbf{\frac{Efficiency\times Total \ Work}{100}}[/tex]
Useful Work = [tex]\mathbf{\frac{81.8\times1100}{100}}[/tex]
Useful Work = 899.8 J
Therefore the amount of useful work done out of total work of 1100 J is 899.8 J by the pulley.
Answer:
The useful work performed by the pulley is, E = 899.8 J
Explanation:
Given data,
The efficiency of a pulley, Ef = 81.8 %
The work input, [tex]W_{i}[/tex] = 1100 J
The main purpose of the pulley is to change the direction of the force applied.
The formula for useful energy,
[tex]E=\frac{E_{f} }{100}\times W_{i}[/tex]
[tex]E=\frac{81.8}{100}\times1100[/tex]
E = 899.8 J
Hence, the useful work performed by the pulley is, E = 899.8 J
