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The perimeter of a rhombus is 52 cm and one of its diagonals is 10 cm. Find the length of the other diagonal and the area of the rhombus. ​

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scotland1209

Answer:

120cm²

Step-by-step explanation:

1)  Perimeter = 4a

            52    = 4a

              a     = 13

2)A = [tex]\frac{1}{2}[/tex]p [tex]\sqrt{4a^{2} - p^{2} }[/tex]

   insert the diagonal (p) and side (a) into the equation

      = 120cm²

Good evening ,

Answer:

2nd diagona = 24 cm

rhombus area = 120 cm²

Step-by-step explanation:

Look at the photo below for more details.

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:)

Ver imagen profarouk

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