mr. huber bought a block of fudge that weighed 2/5 of a pound. he cut the fudge into 6 equal pieces. what was the weight of each piece of fudge?​

Respuesta :

znk

Answer:

[tex]\large \boxed{\frac{1}{15} \text{ lb}}[/tex]

Step-by-step explanation:

You are starting with ⅖ lb of fudge. Then you cut it into six pieces.

You want to evaluate ⅖ ÷ 6

1. Treat the integer as a fraction

[tex]\dfrac{2}{5}\div{\dfrac{6}{1}}[/tex]

2. Invert the divisor and change divide to multiply

[tex]\dfrac{2}{5}\times{\dfrac{1}{6}}[/tex]

3. Divide numerator and denominator by 2

[tex]\dfrac{1}{5}\times{\dfrac{1}{3}}[/tex]

4. Multiply numerators and denominators

[tex]\dfrac{1}{5}\times{\dfrac{1}{3}} = \mathbf{\dfrac{1}{15}}\\\\\text{Each piece of fudge weighs $\large \boxed{\mathbf{\frac{1}{15}} \textbf{ lb}}$}[/tex]