Answer:
The velocity of jet in still air is [tex]860miles/hour[/tex] and velocity of wind is [tex]140miles/hour[/tex].
Step-by-step explanation:
Let x be the rate of the jet in still air and y be the rate of the wind.
Given:
Velocity against wind, a jet travels 2160 miles in 3 hours.
Velocity against wind [tex]=\frac{2160}{3} = 720 miles/hour[/tex]
Flying with the wind, same jet travels 6000 miles in 6 hours.
Flying with the wind [tex]=\frac{6000}{6} = 1000 miles/hour[/tex]
As such its velocity against wind is [tex]x-y[/tex]
and with wind is [tex]x+y[/tex] therefore
[tex]x-y=720[/tex]------------(1)
[tex]x+y=1000[/tex]---------------(2)
Adding equation 1 and 2.
[tex]2x=1720[/tex]
[tex]x=\frac{1720}{2}[/tex]
[tex]x=860[/tex]
Put x value in equation 2
[tex]860+y=1000[/tex]
[tex]y=1000-860[/tex]
[tex]y=140[/tex]
Hence velocity of jet in still air is [tex]860miles/hour[/tex] and velocity of wind is [tex]140miles/hour[/tex].
