pls help and show work

A boy pushes a 5 kg box across the floor with a force of 25 N. There is a 5 N frictional force opposing him. What is the net force and the acceleration of the box?

(50 N in direction of boy’s push; 4 m/s/s)

(20 N in direction of boy’s push; 10 m/s/s)

(200 N in direction of boy’s push; 4 m/s/s)

(20 N in direction of boy’s push; 4 m/s/s)

"force of 25 N and 5 N frictional force" means the box had force of 25 N and opposite force of 5 N. Let's say the box moved to right with 25 N. Think as integers. 25 to the right means positive. On a number line, the right side has positive numbers while left side has negative numbers. So since it moved to the RIGHT it means positive 25. But there was a frictional force of 5 to the opposite side. If you add 25 and -5, you will get 20. 25+(-5) is same as 25-5. So now you have 20 N, but we don't know the acceleration, so leave that as a variable. Then plug into the equation.

F=ma

20=5a

divide both sides by 5

4=a

the acceleration of the box was 4m/s/s