Answer:
[tex]\frac{7\sqrt{2} }{2}[/tex]
Step-by-step explanation:
The 2 legs are congruent.
Let the leg be x, then using Pythagoras' identity in the right triangle
The square on the hypotenuse is equal to the sum of the squares on the other 2 sides, thus
x² + x² = 7², that is
2x² = 49 ( divide both sides by 2 )
x² = [tex]\frac{49}{2}[/tex] ( take the square root of both sides )
x = [tex]\sqrt{\frac{49}{2} }[/tex]
= [tex]\frac{7}{\sqrt{2} }[/tex] × [tex]\frac{\sqrt{2} }{\sqrt{2} }[/tex]
= [tex]\frac{7\sqrt{2} }{2}[/tex]
