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How many potassium hydroxide (KOH) formula units are present in 6.89 mol of KOH?:
A. 4.1498 × 1024
B. 4.1498 × 1023
C. 8.299 × 1024
D. 8.299 × 1023

Respuesta :

To get the number of formula units of the compound, potassium hydroxide (KOH), we must recall that for every mole of ionic compound, the number of fomula units is 6.022 *10^23 units, or the avogadro's number. Hence, for a 6.89 mol compound, the number of formula units is 4.1498 *10^24 units. Answer is A.
meganpierce070

6.89 mol KOH (6.022 x 10^23 formula units / mole) = 4.1498 x 10^24 formula units

Therefore the correct answer would be A. on edge

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