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The small piston of a hydraulic lift has a diameter of 8.0 cm, and its large piston has a diameter of 40cm. the lift raises a load of 15,000N.
a) Determine the force that must be applied to the small piston.
b) Determine the pressure applied to the fluid in the lift.

Respuesta :

Answer:

Part a)

F = 600 N

Part b)

P = 119366.20 Pascal

Explanation:

Part a)

As we know that by Pascal's law pressure must be transmitted through out the liquid without any change

So pressure at bigger piston = pressure at smaller piston

[tex]\frac{F_1}{A_1} = \frac{F_2}{A_2}[/tex]

[tex]\frac{F_1}{\pi(0.04)^2} = \frac{15000}{\pi(0.20)^2}[/tex]

now by solving above equation we have

[tex]F_1 = \frac{16}{400} (15000)[/tex]

[tex]F_1 = 600 N[/tex]

Part b)

Pressure applied at fluid is given as

[tex]P = \frac{F}{A}[/tex]

[tex]P = \frac{15000}{\pi(0.20)^2}[/tex]

P = 119366.20 Pascal

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