Respuesta :
sin(pi + a) = -sin(a)
sin(4pi/3) = sin(pi + pi/3) = -sin(pi/3)
cos(pi-a) = -cos(a)
cos(5pi/6) = cos(pi -pi/6) = -cos(pi/6)
sin(4pi/3) = sin(pi + pi/3) = -sin(pi/3)
cos(pi-a) = -cos(a)
cos(5pi/6) = cos(pi -pi/6) = -cos(pi/6)
a) sin ( 4π/3 ) = sin 240° = sin ( 180° + 60°) = - sin 60° = [tex]- \frac{ \sqrt{3} }{2} [/tex]
b) cos (5π/6 ) = cos 150° = cos ( 90° + 60° ) = - sin 60°=[tex]- \frac{ \sqrt{3} }{2} [/tex]
b) cos (5π/6 ) = cos 150° = cos ( 90° + 60° ) = - sin 60°=[tex]- \frac{ \sqrt{3} }{2} [/tex]