Answer : The correct option is, (a) [tex]\frac{24}{184}\times 100[/tex]
Solution : Given,
Molar mass of [tex]MgBr_2[/tex] = 184 g/mole
Molar mass of Mg = 24 g/mole
Formula used :
[tex]\%\text{ Composition of Mg}=\frac{\text{Molar mass of Mg}}{\text{Molar mass of }MgBr_2}\times 100[/tex]
Now put all the given values in this formula, we get the percent composition of magnesium.
[tex]\%\text{ Composition of Mg}=\frac{24g/mole}{184g/mole}\times 100[/tex]
[tex]\%\text{ Composition of Mg}=\frac{24}{184}\times 100[/tex]
Therefore, the correct answer is, (a)
