[tex]tan(72)= \frac{y}{x} ; tan(55)= \frac{y}{2.2 + x} [/tex]
[tex]y=xtan(72);y=(2.2+x)tan(55)[/tex]
So we are to merge the two equations into one, since both of the equations are equal to y. a = b, b = c therefore, a = c.
[tex]xtan(72)=2.2tan(55)+xtan(55)[/tex]
We are to isolate x.
[tex]x[tan(72)-tan(55)]=2.2tan(55)[/tex]
[tex]x=\frac{2.2tan(55)}{tan(72)-tan(55)}[/tex]
The value of x is approximately, 1.9047m
Then, substitute the value of x from [tex]y=xtan(72)[/tex]
[tex]y=1.9047tan(72)[/tex]
y = 5.862m
Round up, then the answer would be D.