Answer:
The solution is the point (-5,-3)
Step-by-step explanation:
The complete question is
Consider the linear system of equations y = 2/5x - 1 and 2x -3y + 1 = 0
The solution of the system of equations is?
we have
[tex]y=\frac{2}{5}x-1[/tex] ----> equation A
[tex]2x-3y+1=0[/tex] ----> equation B
Solve by substitution
substitute the equation A in equation B
[tex]2x-3(\frac{2}{5}x-1)+1=0[/tex]
solve for x
[tex]2x-\frac{6}{5}x+3+1=0[/tex]
[tex]2x-\frac{6}{5}x+4=0[/tex]
Multiply by 5 both sides to remove the fraction
[tex]10x-6x+20=0[/tex]
[tex]4x+20=0[/tex]
subtract 20 both sides
[tex]4x=-20[/tex]
divide by 4 both sides
[tex]x=-5[/tex]
Find the value of y
[tex]y=\frac{2}{5}(-5)-1[/tex]
[tex]y=-3[/tex]
The solution is the point (-5,-3)
