Answer:
[tex]7\dfrac{1}{9}\ m^2[/tex]
Step-by-step explanation:
If the length of the square side is a units, then the area of the square is
[tex]A=a^2\ un^2.[/tex]
In your case, the side length is
[tex]a=2\dfrac{2}{3}\ m,[/tex]
then the area is
[tex]A=2\dfrac{2}{3}\cdot 2\dfrac{2}{3}\\ \\ \\A=\dfrac{2\cdot 3+2}{3}\cdot \dfrac{2\cdot 3+2}{3}\\ \\ \\A=\dfrac{8}{3}\cdot \dfrac{8}{3}\\ \\ \\A=\dfrac{64}{9}\\ \\ \\A=7\dfrac{1}{9}\ m^2[/tex]
