For this case we must simplify the following expression:
[tex]\frac {1} {2} (6 \frac {2} {3} + \frac {1} {4}) - \frac {5} {24} =[/tex]
We convert the mixed number to an improper fraction:
[tex]6 \frac {2} {3} = \frac {3 * 6 + 2} {3} = \frac {20} {3}[/tex]
So, by rewriting we have:
[tex]\frac {1} {2} (\frac {20} {3} + \frac {1} {4}) - \frac {5} {24} =\\\frac {1} {2} (\frac {4 * 20 + 3 * 1} {4 * 3}) - \frac {5} {24} =\\\frac {1} {2} (\frac {80 + 3} {12}) - \frac {5} {24} =\\\frac {1} {2} (\frac {83} {12}) - \frac {5} {24} =[/tex]
[tex]\frac {83} {24} - \frac {5} {24} =\\\frac {83-5} {24} =\\\frac {78} {24} =\\\frac {39} {12} =\\\frac {13} {4} =\\3 \frac {1} {4}[/tex]
Answer:
[tex]3 \frac {1} {4}[/tex]
