Mike had 2/3 of a cake. He cut 3/4 of the cake to wrap and store in the freezer.
He ate the remaining portion
How much of the cake did he eat

A. 3/4
B. 1/4
C. 1/2
D. 1/8
E. 1/6
E

Respuesta :

The portion of cake Mike ate is 1/6.

The numbers given are expressed as fractions. Fractions are numbers that consist of numerators and denominators. For example, in the fraction 2/3, 2 is the numerator and 3 is the denominator.

The first step is to determine which portion of the cake that was stored in the freezer.

Portion kept in the freezer = 2/3 x 3/4 = 1/2

The second step is to determine the amount of cake Mike ate.

2/3 - 1/2

[tex]\frac{4 - 3}{6}[/tex] = [tex]\frac{1}{6}[/tex]

To learn more about fractions, please check: https://brainly.com/question/25779356

The portion of the cake that Mike ate is [tex]\frac{1}{6}[/tex].

The given parameters:

  • Original fraction of cake Mike possessed = 2/3
  • Fraction of the cake Mike stored = 3/4

The portion of the cake that Mike wrapped and stored in the freezer is calculated as follows;

[tex]= \frac{3}{4} \times \frac{2}{3} \\\\= \frac{1}{2}[/tex]

The portion of the cake that Mike ate is calculated as follows;

[tex]remaining = original - portion \ stored\\\\remaining = \frac{2}{3} - \frac{1}{2} = \frac{4 - 3}{6} = \frac{1}{6}[/tex]

Thus, the portion of the cake that Mike ate is [tex]\frac{1}{6}[/tex].

Learn more about Fractions here: https://brainly.com/question/17220365