Respuesta :

DeanR

Just to be different we'll start with intercept intercept form which says the line through x intercept (a,0) and y intercept (0,b) is

[tex]\dfrac x a + \dfrac y b = 1[/tex]

Through (4,0) and (0,-2) that's

[tex]\dfrac{x}{4} + \dfrac{y}{-2} = 1[/tex]

Multiply through by the common denominator of 4 for standard form:

x - 2y = 4

For slope intercept form we solve for y

-2 y = -x + 4

y = (1/2) x - 2

We see our slope is (1/2) and we go through (4,0) so point slope form is

y - 0 = (1/2)(x - 4)

y = (1/2)(x-4)