?? “solve the missing elements for each problem. use 3.14 for area

Answer:
Problem 4:
Radius = 11 cm.
Circumference = 69.08 cm.
Problem 5:
Radius = 14 mm.
Circumference = 87.92 mm.
Problem 6:
Radius = 9 inches.
Circumference = 56.52 inches.
Problem 7:
Diameter = 32 ft.
Circumference = 100.48 ft.
Problem 8:
Diameter = 26 yards.
Circumference = 81.64 yards.
Problem 9:
Diameter = 12 cm.
Circumference = 37.68 cm.
Step-by-step explanation:
Problem 4:
Given:
Diameter GH = 22 cm
We need to find the radius EF and Circumference of the circle.
Now radius is given by half of the diameter
Also Circumference is given by π times diameter.
Radius EF = [tex]\frac{1}{2}\times Diameter = \frac{1}{2}\times 22 = 11 \ cm[/tex]
Circumference = [tex]\pi \times Diameter = 3.14 \times 22 = 69.08\ cm[/tex]
Hence Radius = 11 cm
Circumference = 69.08 cm.
Problem 5:
Given:
Diameter OP = 28 mm
We need to find the radius MN and Circumference of the circle.
Now radius is given by half of the diameter
Also Circumference is given by π times diameter.
Radius MN = [tex]\frac{1}{2}\times Diameter = \frac{1}{2}\times 28 = 14 \ mm[/tex]
Circumference = [tex]\pi \times Diameter = 3.14 \times 28 = 87.92\ mm[/tex]
Hence Radius = 14 mm
Circumference = 87.92 mm.
Problem 6:
Given:
Diameter EF = 18 inches
We need to find the radius CD and Circumference of the circle.
Now radius is given by half of the diameter
Also Circumference is given by π times diameter.
Radius CD = [tex]\frac{1}{2}\times Diameter = \frac{1}{2}\times 18 = 9 \ in[/tex]
Circumference = [tex]\pi \times Diameter = 3.14 \times 18 = 56.52\ in[/tex]
Hence Radius = 9 inches.
Circumference = 56.52 inches.
Problem 7:
Given:
Radius GH = 16 ft
We need to find the Diameter CD and Circumference of the circle.
Now Diameter is given by twice the radius.
Also Circumference is given by π times diameter.
Diameter KJ = [tex]2 \times radius = 2 \times 16 = 32 \ ft[/tex]
Circumference = [tex]\pi \times Diameter = 3.14 \times 32 = 100.48\ ft[/tex]
Hence Diameter = 32 ft.
Circumference = 100.48 ft.
Problem 8:
Given:
Radius LM = 13 yards
We need to find the Diameter CD and Circumference of the circle.
Now Diameter is given by twice the radius.
Also Circumference is given by π times diameter.
Diameter NO = [tex]2 \times radius = 2 \times 13 = 26 \ yards[/tex]
Circumference = [tex]\pi \times Diameter = 3.14 \times 26 = 81.64\ yards[/tex]
Hence Diameter = 26 yards.
Circumference = 81.64 yards.
Problem 9:
Given:
Radius NO = 6 cm
We need to find the Diameter CD and Circumference of the circle.
Now Diameter is given by twice the radius.
Also Circumference is given by π times diameter.
Diameter PQ = [tex]2 \times radius = 2 \times 6 = 12 \ cm[/tex]
Circumference = [tex]\pi \times Diameter = 3.14 \times 12 = 37.68\ cm[/tex]
Hence Diameter = 12 cm.
Circumference = 37.68 cm.