Answer:
18 feet
Step-by-step explanation:
Given:
A cat is running away from a dog.
After 5 seconds it is 16 feet away from the dog
After 11 seconds it is 28 feet away from the dog.
Let x represent the time in seconds that have passed and y represent the
distance in feet, so there are two points are formed such as (5, 16) and (11,28).
We will find the distance between dog and cat. by using distance formula of the two points.
[tex]d=\sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2} }[/tex]
Now we substitute the given value in above equation.
[tex]d=\sqrt{(11-5)^{2}+(28-11)^{2} }[/tex]
[tex]d=\sqrt{(6)^{2}+(17)^{2} }[/tex]
[tex]d=\sqrt{36+289}[/tex]
[tex]d=\sqrt{325}[/tex]
[tex]d=18.08\ feet[/tex]
18.08 ≅ 18
So [tex]d=18\ feet[/tex]
Therefore the distance between dog and cat is 18 feet.
