Answer:
26. Mass of sugar = 100 g
27. a).m/m % = 8.67 %
b).m/m% = 20%
28.a). Mass of sugar = 12.5 g
b).Mass of sugar = 12.5 g
c).Mass of sugar = 30 g
Explanation:
26. Use formula:
[tex]m/m = \frac{mass\ of\ solute}{mass\ of\ solution} \times 100[/tex]
m/m = 20%
mass of solution = 500 g
mass of Solute = mass of sugar = ?
insert in the formula,
[tex]20 = \frac{mass\ of\ solute}{500} \times 100[/tex]
[tex]mass\ of\ solute = 20 \times 5[/tex]
mass of solute = 100 g
27. a)
[tex]m/m = \frac{mass\ of\ solute}{mass\ of\ solution} \times 100[/tex]
mass of Barium hydroxide(solute) = 13 g
mass of solution = 150 g
[tex]m/m = \frac{13}{150} \times 100[/tex]
m/m % = 8.67 %
b).
[tex]m/m = \frac{mass\ of\ solute}{mass\ of\ solution} \times 100[/tex]
mass of Glucose (solute) = 50 g
mass of solution = 250 g
[tex]m/m = \frac{50}{250} \times 100[/tex]
m/m% = 20%
28. a)
[tex]m/m = \frac{mass\ of\ solute}{mass\ of\ solution} \times 100[/tex]
m/m% = 5
mass of solution = 250 g
mass of solute = ?
[tex]mass\ of\ solute= \frac{mass\ of\ solution}{100} \times m/m[/tex]
[tex]mass\ of\ solute= \frac{250}{100} \times 5[/tex]
mass of sugar = 12.5 g
b).
m/m% = 2.5%
mass of solution = 500 g
mass of solute = ?
[tex]mass\ of\ solute= \frac{mass\ of\ solution}{100} \times m/m[/tex]
[tex]mass\ of\ solute= \frac{500}{100} \times 2.5[/tex]
mass of sugar = 12.5 g
c).
m/m% = 3 %
mass of solution = 1 kg = 1000 g
mass of solute = ?
[tex]mass\ of\ solute= \frac{1000}{100} \times 3[/tex]
Mass of sugar = 30 g
