Answer:
30.11°
Explanation:
[tex]\mu[/tex] = Coefficient of friction = 0.58
g = Acceleration due to gravity = 9.81 m/s²
[tex]\theta[/tex] = Angle of incline
As the forces of the system are conserved we have
[tex]mgsin\theta-\mu mgcos\theta=0\\\Rightarrow mgsin\theta=\mu mgcos\theta\\\Rightarrow sin\theta=\mu cos\theta\\\Rightarrow \mu=\dfrac{sin\theta}{cos\theta}\\\Rightarrow \mu=tan\theta\\\Rightarrow \theta=tan^{-1}\mu\\\Rightarrow \theta=tan^{-1}0.58\\\Rightarrow \theta=30.11^{\circ}[/tex]
The angle of incline is 30.11°
