Answer:
At time t = 0.408 sec diver will be at maximum height
Step-by-step explanation:
We have given equation of the height [tex]f(t)=-4.9t^2+4t+9[/tex]
We know that velocity is the rate of change of distance with respect to time
So [tex]v=\frac{df(t)}{dt}=\frac{df(-4.9t^2+4t+10)}{dt}=-9.8t+4+0=-9.8t+4[/tex]
At maximum height velocity will be zero
So [tex]-9.8t+4=0[/tex]
t = 0.408 sec
So at time t = 0.408 sec diver will be at maximum height
