Answer:
[tex](\,(\frac{2}{3})^\frac{1}{4} \, , \, +\infty \, )[/tex]
Step-by-step explanation:
If x is equal to 0, the equation is not satisfied, otherwise
[tex]2x^{10}*x^3 < 3x^9x^8 \, \Leftrightarrow \, 2x^{13} < 3x^{17} \, \Leftrightarrow \, \frac{2}{3} < x^4 \, \Leftrightarrow \, x > (2/3)^{1/4}[/tex]
So, for x greater than [tex] (2/3)^{1/4}[/tex] , the equation is valid. The interval solution is [tex](\,(\frac{2}{3})^\frac{1}{4} \, , \, +\infty \, )[/tex]
