The force exerted on the bumper is 1397 N
Explanation:
We can solve this problem by using the equilibrium of the torques: in fact, the torque exerted on one side of the jack must be equal to the torque exerted on the other side of the jack.
Therefore, we can write:
[tex]F_h d_h = F_b d_b[/tex]
where
[tex]F_h = 163 N[/tex] is the force applied to the end of the jack handle
[tex]d_h = 15 cm[/tex] is the distance between the force applied on the handle and the pivot
[tex]F_b[/tex] is the force exerted by the jack on the car bumper
[tex]d_b = 1.75 cm[/tex] is the distance between this force and the car bumper
And solving for [tex]F_b[/tex], we find:
[tex]F_b = \frac{F_h d_h}{d_b}=\frac{(163)(15)}{1.75}=1397 N[/tex]
Learn more about levers and torques:
brainly.com/question/5352966
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