Answer:
a. 0.28 L
Explanation:
At constant pressure and number of moles, Using Charle's law
[tex]\frac {V_1}{T_1}=\frac {V_2}{T_2}[/tex]
Given ,
V₁ = 0.25 L
V₂ = ?
T₁ = 0 °C
T₂ = 35 °C
The conversion of T( °C) to T(K) is shown below:
T(K) = T( °C) + 273.15
So,
T₁ = (0 + 273.15) K = 273.15 K
T₂ = (35 + 273.15) K = 308.15 K
Using above equation as:
[tex]\frac{0.25}{273.15}=\frac{V_2}{308.15}[/tex]
[tex]V_2=\frac{0.25\cdot \:308.15}{273.15}[/tex]
New volume = 0.28 L