A cylinder with a movable piston contains a fixed amount of gas at a constant pressure. Initially, the cylinder contains 0.25 liters of air at 0 degrees Celsius. When the temperature is increased to 35 degrees Celsius, the air will occupy what volume?
a. 0.28 L

b. 0.88 L

c. 8.75 L

d. 35.25 L

Respuesta :

Answer:

a. 0.28 L

Explanation:

At constant pressure and number of moles, Using Charle's law  

[tex]\frac {V_1}{T_1}=\frac {V_2}{T_2}[/tex]

Given ,  

V₁ = 0.25 L

V₂ = ?

T₁ = 0 °C

T₂ = 35 °C  

The conversion of T( °C) to T(K) is shown below:

T(K) = T( °C) + 273.15  

So,  

T₁ = (0 + 273.15) K = 273.15 K  

T₂ = (35 + 273.15) K = 308.15 K  

Using above equation as:

[tex]\frac{0.25}{273.15}=\frac{V_2}{308.15}[/tex]

[tex]V_2=\frac{0.25\cdot \:308.15}{273.15}[/tex]

New volume = 0.28 L