A virus takes 8 days to double its original population (A=2A0). How long will it take to quadruple its population? Round to the nearest tenth.

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Answer:

It takes 16 days to quadruple its population.

Step-by-step explanation:

The population of the virus can be represented by the following exponential function.

[tex]A(t) = A_{0}e^{rt}[/tex]

In which A(t) is the population after t days, [tex]A_{0}[/tex] is the initial population and r is the growth rate.

In this problem, we have that:

[tex]A(8) = 2A_{0}[/tex]

So, we use this to find the value of r.

[tex]A(t) = A_{0}e^{rt}[/tex]

[tex]2A_{0} = A_{0}e^{8r}[/tex]

[tex]e^{8r} = 2[/tex]

Applying ln to both sides

[tex]8r = 0.6931[/tex]

[tex]r = 0.0867[/tex]

How long will it take to quadruple its population?

This is t when [tex]A(t) = 4A_{0}[/tex]

[tex]A(t) = A_{0}e^{rt}[/tex]

[tex]4A_{0} = A_{0}e^{0.0867t}[/tex]

[tex]e^{0.0867t} = 4[/tex]

Again we apply ln to both sides.

[tex]0.0867t = 1.39[/tex]

[tex]t = 16[/tex]

It takes 16 days to quadruple its population.

The number of days it takes to quadruple it's population is; 16days

According to the question;

  • The virus takes 8 days to double it's original population.

Therefore;

8days = 2A.

We are required to determine how long it will take to quadruple it's population;

Let no. of days required = x days.

  • 8days =======2A

  • x days =======4A

By cross multiplication; we have;

  • 2Ax = 32A

By dividing through by 2A; we have;

  • x = 16 days.

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