Answer:
B. [tex]\frac{1}{x^2y^7}[/tex]
Step-by-step explanation:
Given:
[tex](x^3y^{-2}z)(x^{-5}y^{-5}z^{-1})[/tex]
Hence Solving the given expression we get;
By Law of Indices which states;
[tex](a^xb^yc^z)(a^pb^qc^r) = a^{x+p}b^{y+q}c^{z+r}[/tex]
Hence we get;
[tex]x^{3+(-5)}y^{(-2)+(-5)}z^{1+(-1)}\\\\x^{3-5}y^{-2-5}z^{1-1}\\\\x^{-2}y^{-7}[/tex]
Also We know that
[tex]a^{-6} =\frac{1}{a^6}[/tex]
So,
[tex]\frac{1}{x^2y^7}[/tex]
