Answer:
The width of both rectangles are [tex]\frac{36}{l},\frac{21}{L}[/tex].
Step-by-step explanation:
Given : The area of one rectangle is 36 square feet. The area of a second rectangle is 21 square feet. The rectangles have the same width and the dimensions are whole numbers.
To find : What is the width of both rectangles?
Solution :
According to question, the two rectangles have the same widths but they have different lengths.
Let the width of both rectangle be 'w'
Let the length of one rectangle be 'l'
Let the length of second rectangle be 'L'
The area of the rectangle is [tex]\text{Area}=\text{Length}\times \text{Width}[/tex]
The area of one rectangle,
[tex]36=l\times w[/tex]
[tex]w=\frac{36}{l}[/tex]
The area of second rectangle,
[tex]21=L\times w[/tex]
[tex]w=\frac{21}{L}[/tex]
The width of both rectangles are [tex]\frac{36}{l},\frac{21}{L}[/tex].
