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Old Isaac took a little nosedive from his perch on top of the building, 25 feet above ground. Given that he fell as a result of a gentle tap to his noggin (initial velocity was zero), how fast is Isaac traveling when he hits the ground? (In case you forgot, acceleration due to gravity is -32 ft/sec2 .) Make sure your answer is in feet/sec. Leave your reply under the brick beside your car.

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Answer:

40 ft/s

Explanation:

t = Time taken

u = Initial velocity

v = Final velocity

s = Displacement

g = Acceleration due to gravity = -32 ft/s² = a (downward is taken a negative)

Equation of motion

[tex]v^2-u^2=2as\\\Rightarrow v=\sqrt{2as+u^2}\\\Rightarrow v=\sqrt{2\times -32\times -25+0^2}\\\Rightarrow v=40\ ft/s[/tex]

The speed of Isaac as he reached the ground is 40 ft/s